22 lines
822 B
Python
22 lines
822 B
Python
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from numpy.core.defchararray import startswith
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if __name__ == '__main__':
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str = "https://www.baidu.com"
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str2 = "http://www.baidu.cn"
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str3 = "suka"
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# 如果想要在字符串首进行匹配，可以使用：
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is_start_with_https = str.startswith("https")
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print(is_start_with_https)
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# 这会输出一个布尔值，
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## 比如上面匹配成功，就会输出True
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# 同理，可以设置endswith
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is_end_with_dotcom = str.endswith(".com")
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print(is_end_with_dotcom)
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# 如果想要匹配多种开头和结尾，可以将函数输入改成元组()
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is_url = [url for url in [str, str2, str3] if url.startswith(('http', 'https'))]
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print(is_url)
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# 当然，复杂的操作还请使用正则表达式进行匹配，不过简单的检查用这个方法那是又快又好
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